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x^2+x=6/25
We move all terms to the left:
x^2+x-(6/25)=0
We add all the numbers together, and all the variables
x^2+x-(+6/25)=0
We get rid of parentheses
x^2+x-6/25=0
We multiply all the terms by the denominator
x^2*25+x*25-6=0
Wy multiply elements
25x^2+25x-6=0
a = 25; b = 25; c = -6;
Δ = b2-4ac
Δ = 252-4·25·(-6)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*25}=\frac{-60}{50} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*25}=\frac{10}{50} =1/5 $
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